Exam Dumps Oracle 1z0-071 Provider & Vce 1z0-071 File
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Oracle 1z0-071 Exam is a computer-based exam that lasts for 120 minutes. 1z0-071 exam consists of 73 multiple-choice questions, and the passing score is 63%. 1z0-071 exam is available in different languages, including English, Japanese, Korean, Portuguese, and Chinese. It can be taken at any authorized Oracle testing center or online through Oracle's remote proctoring service.
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Oracle Database SQL Sample Questions (Q84-Q89):
NEW QUESTION # 84
Examine this query:
SELECT INTERVAL '100' MONTH DURATION FROM DUAL;
What will be the output?
- A. DUFATION
+100 - B. DURATION
+08 - C. an error
- D. DURATION
+08-04
Answer: D
NEW QUESTION # 85
The ORDERStable has a column ORDER_DATE of data type DATE.
The default display format for a date is DD-MON-RR.
Which two WHEREconditions demonstrate the correct usage of conversion functions? (Choose two.) WHERE TO_CHAR(order_date, 'MON DD YYYY') = 'JAN 20 2019'
- A. WHERE order_date > TO_DATE('JUL 10 2018', 'MON DD YYYY')
- B. WHERE order_date > TO_CHAR(ADD_MONTHS(SYSDATE,6), 'MON DD YYYY')
- C. WHERE order_date IN (TO_DATE('OCT 21 2018', 'Mon DD YYYY'), TO_CHAR('Nov 21
- D. WHERE order_date > TO_DATE(ADD_MONTHS(SYSDATE,6), 'MON DD YYYY')
- E. 2018', 'Mon DD YYYY'))
Answer: A,B
Explanation:
Explanation/Reference: https://ss64.com/ora/syntax-to_date.html
NEW QUESTION # 86
View the Exhibit and examine the structure of the EMPLOYEES table.
You want to display all employees and their managers having 100 as the MANAGER_ID.
You want the output in two columns: the first column would have the LAST_NAME of the managers and the second column would have LAST_NAME of the employees.
Which SQL statement would you execute?
- A. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE m.manager_id=100; - B. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE e.managerjd=100; - C. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON e.employee_id = m.manager_id
WHERE m.manager_id=100; - D. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
WHERE m.employee_id = e.manager_id AND e.managerjd=100;
Answer: B
NEW QUESTION # 87
Examine the description of the PROMTIONS table:
You want to display the unique promotion costs in each promotion category.
Which two queries can be used?
- A. SELECT promo_cost, | pxomo_category FROM promotions ORDER BY 1;
- B. SELECT DISTINCT promo_category ||'has'|| promo_cost AS COSTS FROM promotions ORDER BY 1;
- C. SELECT DISTINCT promo_cost ||' in' II DISTINCT promo_category FROM promotions ORDER BY 1;
- D. SELECT promo_category, DISTINCT promo_cost PROM promotions ORDER BY 2:
- E. SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1;
Answer: B,E
NEW QUESTION # 88
View the Exhibit and examine the structure of ORDERSand CUSTOMERStables.
You executed this UPDATEstatement:
Which statement is true regarding the execution? (Choose the best answer.)
- A. It would execute and restrict modifications to the columns specified in the SELECTstatement.
- B. It would not execute because a SELECTstatement cannot be used in place of a table name.
- C. It would not execute because a subquery cannot be used in the WHEREclause of an UPDATEstatement.
- D. It would not execute because two tables cannot be referenced in a single UPDATEstatement.
Answer: A
Explanation:
Explanation/Reference:
NEW QUESTION # 89
......
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